Vedic
Mathematics
Suthra 1 : Ekadhikena Purvena
Application : Recurring
Decimal Expansion of Vulgar Fractions with denominator ending with ‘9’.
Meaning : By One More than the Previous One
We can apply the same suthra to find
out the decimal representation(Recurring Decimal) of VULGAR fractions with denominator ending with
the digit ‘9’.
First Method : Division Method
Let us use this suthra to find out
the recurring decimal of
1/19
Here the number of decimal places
before repetition is
“Difference of Numerator and
Denominator”
i.e., 19 – 1 = 18 places
In this fraction, 1/19, “Purva”(before
9) is 1
Hence “Ekadhikena Purvena” means 1 +
1 =2
While applying “Ekadhikena Purvena”
We have
Step 1 : Divide numerator 1 by 20
1/20
= 0.1/2 = 10 (0 times, 1 remainder)
Step 2 : Divide 10 by 2
0.005(5 times, o remainder)
Step 3 : Divide 5 by 2
0.0512 (2 times, 1 reminder)
Step 4 : Divide 12 I.e., 12
by 2
0.05206(6 times, 0 reminder)
Step 5 : Divide 6 by 2
0.052603(3 times, 0 reminder)
Step 6 : Divide 3 by 2
0.0526311(1 times, 1 remainder)
Step 7 : Divide 11 by 2
0.05263115(5 times, 1 reminder)
Step 8 : Divide 15 by 2
0.052631517 (7 times, 1 remainder)
Step 9 : Divide 17 by 2
0.0526315718(8 times, 1 reminder)
Step 10 : Divide 18 by 2
0.05263157809(9 times, 0 remainder)
Step 11 : Divide 9 by 2
0.052631578914(4
times, 1 remainder)
Step 12 : Divide 14 by 2
0.0526315789417(7
times, 1 remainder)
Step 13 : Divide 7 by 2
0.05263157894713(3
times, 1 reminder)
Step 14 : Divide 13 by 2
0.052631578947316(6
times, 1 reminder)
Step 15 : Divide 16 by 2(8 times, 0
remainder)
0.0526315789473608
Step 16 : Divide 8 by 2(4 times, 0
remainder)
0.05263157894736804
Step 17 : Divide 4 by 2(2 times, 0
remainder)
0.052631578947368402
Step 8 : Divide 2 by 2(1 time, 0
remainder)
0.052631578947368421
Hence 1/19 = 0. 052631578947368421052631578947368421……….
Good explanation
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